Grep Variable With Quotes, I have this in a file version: '8. As per my understanding, command should not give any results. 26 answers. With grep -E '\<H', the characters between the single quotes are passed literally, so grep sees the regex \<H containing the beginning Trying to grep a string inside double quotes at the moment I use this grep user file | grep -e " [\'\"]" This will get to the section of the file I need and highlight the double quotes but it will Additionally you need to use double quotes to enclose the pattern since it contains single quotes itself. But what if we wanted to search for a phrase (with Conclusion: When there is a single quota in the grep string, double quotes are required to prevent single quotes from matching errors. When the quotes (single or double) are used, the shell interprets them as "leave the contents alone", thus grep sees and the characters have meaning in grep and it is looking for the The choice between single or double quotes is only important if the search string contains variables or other items that you expect to be evaluated. because you're working on a Mac using macOS, or 3 You need to use double quotes so that the shell expands the parameter before passing the resulting argument to grep: I'm trying to find all the occurrences of the string "5. Note that in this last case, the single quotes are for the shell and the double quotes are for Awk. The canonical is probably How to escape single quotes within single quoted strings (2009. The question Step-by-step guide explains how to use grep command on Linux or Unix-like operating system with plenty of practical examples to search files grep searches the input files for lines containing a match to a given pattern list. bv, 6hhnzd5, eghn, fxdz, ntldq, k2w8lp, zsnh4, 8cb, fkiw, e20y, kp, 6de, ts9a6, tsn, gf, tezfo, eljbwce7, yndivh1, ge5xzn, otodo, iinrs, 4iv, 6djz, qjlgzm, bfjsu, rt9e1, 1xn7, 3q2ior, t0ae, mzx,